If $A, B$,and $C$ are three sets,then $A \times (B \cup C)$ is equal to
- A$(A \times B) \cup (A \times C)$
- B$(A \cup B) \times (A \cup C)$
- C$(A \times B) \cap (A \times C)$
- DNone of these
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Similar Questions
Write the following set in roster form:
$A = \{ x : x \text{ is an integer and } -3 < x < 7 \}$
$A = \{ x : x \text{ is an integer and } -3 < x < 7 \}$
Easy
View SolutionLet $A = \{1, 2, \{3, 4\}, 5\}$. Which of the following statements is incorrect and why?
${1, 2, 5} \subset A$
${1, 2, 5} \subset A$
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View SolutionShow that if $A \subset B$,then $(C - B) \subset (C - A)$.
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View SolutionMatch each of the set on the left in the roster form with the same set on the right described in set-builder form:
$(i)$ $\{1, 2, 3, 6\}$ $(a)$ $\{x : x \text{ is a prime number and a divisor of } 6\}$ $(ii)$ $\{2, 3\}$ $(b)$ $\{x : x \text{ is an odd natural number less than } 10\}$ $(iii)$ $\{M, A, T, H, E, I, C, S\}$ $(c)$ $\{x : x \text{ is a natural number and divisor of } 6\}$ $(iv)$ $\{1, 3, 5, 7, 9\}$ $(d)$ $\{x : x \text{ is a letter of the word } MATHEMATICS\}$
| $(i)$ $\{1, 2, 3, 6\}$ | $(a)$ $\{x : x \text{ is a prime number and a divisor of } 6\}$ |
| $(ii)$ $\{2, 3\}$ | $(b)$ $\{x : x \text{ is an odd natural number less than } 10\}$ |
| $(iii)$ $\{M, A, T, H, E, I, C, S\}$ | $(c)$ $\{x : x \text{ is a natural number and divisor of } 6\}$ |
| $(iv)$ $\{1, 3, 5, 7, 9\}$ | $(d)$ $\{x : x \text{ is a letter of the word } MATHEMATICS\}$ |
Medium
View SolutionLet $A = \{1, 2, \{3, 4\}, 5\}$. Which of the following statements is incorrect and why?
${1, 2, 5} \in A$
${1, 2, 5} \in A$
Easy
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