If Q = {x : x = frac{1}{y}, y in N},then whic | vedclass

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(B) The set $Q$ is defined as $Q = \{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \dots\}$.Since $y \in N$ (where $N = \{1, 2, 3, \dots\}$),the smallest

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$1 \in Q$

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(B) The set $Q$ is defined as $Q = \{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \dots\}$.Since $y \in N$ (where $N = \{1, 2, 3, \dots\}$),the smallest value for $y$ is $1$.For $y = 1$,$x = \frac{1}{1} = 1$.Therefore,$1 \in Q$ is true.For $0 \in Q$,we would need $\frac{1}{y} = 0$,which is impossible for any finite $y \in N$.For $2 \in Q$,we would need $\frac{1}{y} = 2$,so $y = \frac{1}{2}$,which is not a natural number.For $\frac{2}{3} \in Q$,we would need $\frac{1}{y} = \frac{2}{3}$,so $y = \frac{3}{2}$,which is not a natural number.Thus,the correct option is $B$.

If $Q = \{x : x = \frac{1}{y}, y \in N\}$,then which of the following is true?

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