Let A = {11, 12, 13} and B = {8, 10, 12}. A r | vedclass

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(A) Given sets are $A = \{11, 12, 13\}$ and $B = \{8, 10, 12\}$.The relation $R$ is defined as $y = x - 3$,where $x \in A$ and $y \in B$.For $x = 11$,

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$\{(8, 11), (10, 13)\}$

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(A) Given sets are $A = \{11, 12, 13\}$ and $B = \{8, 10, 12\}$.The relation $R$ is defined as $y = x - 3$,where $x \in A$ and $y \in B$.For $x = 11$,$y = 11 - 3 = 8$. Since $8 \in B$,$(11, 8) \in R$.For $x = 12$,$y = 12 - 3 = 9$. Since $9 
otin B$,$(12, 9) 
otin R$.For $x = 13$,$y = 13 - 3 = 10$. Since $10 \in B$,$(13, 10) \in R$.Thus,$R = \{(11, 8), (13, 10)\}$.The inverse relation $R^{-1}$ is obtained by interchanging the elements of the ordered pairs in $R$.Therefore,$R^{-1} = \{(8, 11), (10, 13)\}$.

Let $A = \{11, 12, 13\}$ and $B = \{8, 10, 12\}$. $A$ relation $R$ from $A$ to $B$ is defined by $y = x - 3$. Then,find $R^{-1}$.

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