Let A = {1, 2, 3} and B = {1, 3, 5}. If a rel | vedclass

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(A) The relation $R$ is given by $R = \{(1, 3), (2, 5), (3, 3)\}$.By definition,the inverse relation $R^{-1}$ is obtained by interchanging the element

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$\{(3, 3), (3, 1), (5, 2)\}$

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(A) The relation $R$ is given by $R = \{(1, 3), (2, 5), (3, 3)\}$.By definition,the inverse relation $R^{-1}$ is obtained by interchanging the elements of the ordered pairs in $R$.That is,if $(a, b) \in R$,then $(b, a) \in R^{-1}$.Applying this to each element of $R$:$(1, 3) \in R \implies (3, 1) \in R^{-1}$$(2, 5) \in R \implies (5, 2) \in R^{-1}$$(3, 3) \in R \implies (3, 3) \in R^{-1}$Therefore,$R^{-1} = \{(3, 1), (5, 2), (3, 3)\}$.Rearranging the set,we get $R^{-1} = \{(3, 3), (3, 1), (5, 2)\}$.Thus,the correct option is $A$.

Let $A = \{1, 2, 3\}$ and $B = \{1, 3, 5\}$. If a relation $R$ is defined from $A$ to $B$ as $R = \{(1, 3), (2, 5), (3, 3)\}$,then find $R^{-1}$.

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