What is the remainder when the polynomial P(x | vedclass

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(C) According to the Remainder Theorem,when a polynomial $P(x)$ is divided by $(x - a)$,the remainder is $P(a)$.Here,we are dividing by $(x - 1)$,so $

Vedclass · Accepted Answer

$7$

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(C) According to the Remainder Theorem,when a polynomial $P(x)$ is divided by $(x - a)$,the remainder is $P(a)$.Here,we are dividing by $(x - 1)$,so $a = 1$.We need to calculate $P(1)$:$P(1) = 1 + (1) + (1)^3 + (1)^9 + (1)^{27} + (1)^{81} + (1)^{243}$Since $1^n = 1$ for any positive integer $n$,we have:$P(1) = 1 + 1 + 1 + 1 + 1 + 1 + 1$$P(1) = 7$Therefore,the remainder is $7$.

What is the remainder when the polynomial $P(x) = 1 + x + x^3 + x^9 + x^{27} + x^{81} + x^{243}$ is divided by $x - 1$?

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