If $\frac{3x^2 + 5}{(x^2 + 1)^2} = \frac{a}{x^2 + 1} + \frac{b}{(x^2 + 1)^2}$,then $(a, b) = $

  • A
    $(2, 3)$
  • B
    $(3, 2)$
  • C
    $(-2, 3)$
  • D
    $(-3, 2)$

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