(B) Since a frictional force acts at the point of contact with the ground,the total kinetic energy will not be conserved.However,the torque of this fr

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Angular momentum about the point of contact with the surface is conserved.

(B) Since a frictional force acts at the point of contact with the ground,the total kinetic energy will not be conserved.However,the torque of this frictional force about the point of contact is zero because the force acts exactly at that point.Therefore,the angular momentum of the sphere about the point of contact remains constant.Mathematically,$\vec{\tau} = \frac{d\vec{L}}{dt}$. If $\vec{\tau} = 0$,then $\vec{L} = \text{constant}$.

Class 11 Physics System of Particles and Rotational Motion Rolling motion on horizontal Surface

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$A$ solid homogeneous sphere is rolling with sliding on a horizontal rough surface. For this type of motion of the sphere:

A
Total kinetic energy is conserved.
B
Angular momentum about the point of contact with the surface is conserved.
C
Only rotational kinetic energy about the center of mass is conserved.
D
Angular momentum about the center of mass is conserved.

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System of Particles and Rotational Motion

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Rolling motion on horizontal Surface

$A$ solid sphere of mass $2\,kg$ is making pure rolling on a horizontal surface with kinetic energy $2240\,J$. The velocity of the centre of mass of the sphere will be $..........\,m/s$.

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$A$ sphere of mass $50\,g$ and diameter $20\,cm$ rolls without slipping with a velocity of $5\,cm/s$. Its total kinetic energy is

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Given $V_{CM} = 2\; m/s$,$m = 2\; kg$,$R = 4\; m$. Find the angular momentum of the ring about the origin if it is in pure rolling. (in $kg \cdot m^2/s$)

MediumAIIMS 2019

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$A$ solid disc rolls clockwise without slipping over a horizontal path with a constant speed $v$. Then the magnitude of the velocities of points $A, B$ and $C$ (see figure) with respect to a standing observer are:

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If a solid sphere of mass $1\, kg$ and radius $0.1\, m$ rolls without slipping at a uniform velocity of $1\, m/s$ along a straight line on a horizontal floor,the kinetic energy is (in $, J$)

MediumAIIMS 2007

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$A$ solid homogeneous sphere is rolling with sliding on a horizontal rough surface. For this type of motion of the sphere:

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$A$ solid sphere of mass $2\,kg$ is making pure rolling on a horizontal surface with kinetic energy $2240\,J$. The velocity of the centre of mass of the sphere will be $..........\,m/s$.

$A$ sphere of mass $50\,g$ and diameter $20\,cm$ rolls without slipping with a velocity of $5\,cm/s$. Its total kinetic energy is

Given $V_{CM} = 2\; m/s$,$m = 2\; kg$,$R = 4\; m$. Find the angular momentum of the ring about the origin if it is in pure rolling. (in $kg \cdot m^2/s$)

$A$ solid disc rolls clockwise without slipping over a horizontal path with a constant speed $v$. Then the magnitude of the velocities of points $A, B$ and $C$ (see figure) with respect to a standing observer are:

If a solid sphere of mass $1\, kg$ and radius $0.1\, m$ rolls without slipping at a uniform velocity of $1\, m/s$ along a straight line on a horizontal floor,the kinetic energy is (in $, J$)

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