A solid disc rolls clockwise without slipping | vedclass

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(B) For a disc rolling without slipping,the velocity of any point is the vector sum of its translational velocity $(v)$ and rotational velocity $(r\om

Vedclass · Accepted Answer

$2v, \sqrt{2}v, 0$

Vedclass · Answer

(B) For a disc rolling without slipping,the velocity of any point is the vector sum of its translational velocity $(v)$ and rotational velocity $(r\omega)$. Since it rolls without slipping,$v = r\omega$.$1$. At point $A$ (top): Both translational and rotational velocities are in the same direction (forward). Thus,$v_A = v + r\omega = v + v = 2v$.$2$. At point $B$ (side): The translational velocity is horizontal $(v)$ and the rotational velocity is vertical downward $(v)$. The resultant velocity is $v_B = \sqrt{v^2 + v^2} = \sqrt{2}v$.$3$. At point $C$ (bottom): The translational velocity is forward $(v)$ and the rotational velocity is backward $(v)$. The resultant velocity is $v_C = v - v = 0$.Therefore,the magnitudes are $2v, \sqrt{2}v, 0$. The correct option is $B$.

$A$ solid disc rolls clockwise without slipping over a horizontal path with a constant speed $v$. Then the magnitude of the velocities of points $A, B$ and $C$ (see figure) with respect to a standing observer are:

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