CH_3-CH(CH_3)-CH=CH_2 + HBr rightarrow A. A ( | vedclass

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Question

(D) The reaction proceeds via electrophilic addition involving carbocation rearrangement.Step $1$: Protonation of the alkene gives a secondary $(2^\ci

Vedclass · Accepted Answer

$CH_3-C(Br)(CH_3)-CH_2-CH_3$

Vedclass · Answer

(D) The reaction proceeds via electrophilic addition involving carbocation rearrangement.Step $1$: Protonation of the alkene gives a secondary $(2^\circ)$ carbocation: $CH_3-CH(CH_3)-C^+H-CH_3$.Step $2$: $A$ $1,2$-hydride shift occurs to form a more stable tertiary $(3^\circ)$ carbocation: $CH_3-C^+(CH_3)-CH_2-CH_3$.Step $3$: Nucleophilic attack by $Br^-$ on the $3^\circ$ carbocation yields the major product: $CH_3-C(Br)(CH_3)-CH_2-CH_3$ ($2$-bromo-$2$-methylbutane).

$CH_3-CH(CH_3)-CH=CH_2 + HBr \rightarrow A$. $A$ (predominantly) is:

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