The products Q and R in the following reactio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The reaction of $CH_3-C \equiv CH$ (propyne) with $H_2$ in the presence of Lindlar's catalyst results in the formation of $CH_3-CH=CH_2$ (pro

Vedclass · Accepted Answer

$Ethanal$,$Methanal$

Vedclass · Answer

(C) $1$. The reaction of $CH_3-C \equiv CH$ (propyne) with $H_2$ in the presence of Lindlar's catalyst results in the formation of $CH_3-CH=CH_2$ (propene) as product $P$.$2$. The ozonolysis of propene $(CH_3-CH=CH_2)$ in the presence of $Zn/H_2O$ (reductive ozonolysis) leads to the cleavage of the double bond.$3$. The reaction is: $CH_3-CH=CH_2 + O_3 \xrightarrow{Zn/H_2O} CH_3CHO + HCHO$.$4$. Thus,the products $Q$ and $R$ are $CH_3CHO$ $(Ethanal)$ and $HCHO$ $(Methanal)$.

The products $Q$ and $R$ in the following reactions respectively are:
$H_2 + CH_3-C \equiv CH$ $\xrightarrow{\text{Lindlar's catalyst}} P$ $\xrightarrow[Zn + H_2O]{O_3} Q + R$

Similar Questions

Identify products $[A]$,$[B]$,and $[C]$ in the following reaction sequence:
$CH_3-C \equiv CH$ $\xrightarrow{H_2, Pd/C} [A]$ $\xrightarrow[(ii) Zn, H_2O]{(i) O_3} [B] + [C]$

$But-1-ene$ may be converted to $butane$ by reaction with:

Conjugate double bond is present in

What is the product of the reaction: ${H_2}C = CH{(CH_2)_6}CH_3 \xrightarrow[peroxide]{HBr} ?$

Which compound on reductive ozonolysis produces at least one mole of $CO_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The products $Q$ and $R$ in the following reactions respectively are:$H_2 + CH_3-C \equiv CH$ $\xrightarrow{\text{Lindlar's catalyst}} P$ $\xrightarrow[Zn + H_2O]{O_3} Q + R$