Which compound on reductive ozonolysis produc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds ($aldehydes$ or $ketones$).If the alke

Vedclass · Accepted Answer

$CH_2=C=CH_2$

Vedclass · Answer

(C) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds ($aldehydes$ or $ketones$).If the alkene has a terminal $CH_2$ group (i.e.,$R-CH=CH_2$),it produces formaldehyde $(HCHO)$.If the alkene has a $C=C$ bond where the carbon is bonded to two other groups,it produces ketones.Specifically,for allene $(CH_2=C=CH_2)$,the central carbon atom is bonded to two double bonds. Upon ozonolysis,the central carbon is oxidized to $CO_2$ because it is bonded to two terminal $CH_2$ groups which become formaldehyde $(HCHO)$.The reaction is: $CH_2=C=CH_2 + 2O_3$ $ightarrow 	ext{ozonide intermediate}$ $\xrightarrow{Zn/H_2O} 2HCHO + CO_2$.Thus,$CH_2=C=CH_2$ produces $CO_2$.

Which compound on reductive ozonolysis produces at least one mole of $CO_2$?

Similar Questions

The compound $B$ formed in the following sequence of reactions is:
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{PCl_3} A$ $\xrightarrow{Alco. KOH} B$

An alkene gives two moles of $HCHO$,one mole of $CO_2$,and one mole of $CH_3COCHO$ on ozonolysis. What is its structure?

Alkenes react with water in the presence of acid as a catalyst to form alcohols: $CH_3-CH=CH_2 + H_2O \xrightarrow{H^{+}} CH_3-CH(OH)-CH_3$. The reaction takes place in accordance with:

Find out the major product of the following reaction:
$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F.} \text{?}$

Which of the following reactions results in the formation of a pair of diastereomers?

Vedclass Test Series

Exam Paper Generator

Online Exam Module