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(D) When $n$ identical cells,each with $EMF$ $E$ and internal resistance $r$,are connected in series,the total $EMF$ of the battery is $nE$ and the to

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(D) When $n$ identical cells,each with $EMF$ $E$ and internal resistance $r$,are connected in series,the total $EMF$ of the battery is $nE$ and the total internal resistance is $nr$.When the terminals of the battery are short-circuited,the current $I$ flowing through the circuit is given by:$I = \frac{	ext{Total EMF}}{	ext{Total Resistance}} = \frac{nE}{nr} = \frac{E}{r}$Since $E$ and $r$ are constants for the given cells,the current $I$ is independent of the number of cells $n$. Therefore,the graph of $I$ versus $n$ is a horizontal straight line,indicating that $I$ remains constant as $n$ varies.

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