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(D) Let the radius of each small drop be $R$ and the charge on each be $q$.The potential of each small drop is $V = \frac{kq}{R}$,which implies $q = \

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$Vn^{2/3}$

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(D) Let the radius of each small drop be $R$ and the charge on each be $q$.The potential of each small drop is $V = \frac{kq}{R}$,which implies $q = \frac{VR}{k}$.When $n$ such drops coalesce to form a large drop of radius $R'$,the total volume remains conserved:$\frac{4}{3}\pi (R')^3 = n \cdot \frac{4}{3}\pi R^3 \Rightarrow R' = n^{1/3}R$.The total charge on the large drop is $Q = nq = n \cdot \frac{VR}{k}$.The potential of the large drop $V'$ is given by:$V' = \frac{kQ}{R'} = \frac{k(nVR/k)}{n^{1/3}R} = \frac{nVR}{n^{1/3}R} = V n^{1 - 1/3} = V n^{2/3}$.

$n$ small drops of the same size are charged to $V$ volts each. If they coalesce to form a single large drop,then its potential will be:

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