The VT curve for a thermodynamic process is g | vedclass

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(D) In the given $VT$ diagram:$1$. Process $c \rightarrow a$: $T$ is constant,so it is an isothermal process. In a $PV$ diagram,this is a rectangular

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(D) In the given $VT$ diagram:$1$. Process $c \rightarrow a$: $T$ is constant,so it is an isothermal process. In a $PV$ diagram,this is a rectangular hyperbola. Since $V$ decreases,$P$ must increase.$2$. Process $a \rightarrow b$: This is an adiabatic process. In a $PV$ diagram,the curve is steeper than an isothermal process. Since $V$ increases,$P$ decreases.$3$. Process $b \rightarrow c$: This is a process where the line passes through the origin in the $VT$ diagram,meaning $V \propto T$. From the ideal gas law $PV = nRT$,if $V \propto T$,then $P$ must be constant. Thus,it is an isobaric process. In a $PV$ diagram,this is a horizontal line. Since $V$ increases,the process moves to the right.Comparing these characteristics with the given options,the correct $PV$ curve is represented by Option $D$.

The $VT$ curve for a thermodynamic process is given. Identify the corresponding $PV$ curve.

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