A ring of mass M and radius R sliding with a | vedclass

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Question

(D) When the ring enters the rough surface,it is purely sliding forward with velocity $v_0$ and has no initial angular velocity $(\omega = 0)$.$1$. Si

Vedclass · Accepted Answer

All of the above.

Vedclass · Answer

(D) When the ring enters the rough surface,it is purely sliding forward with velocity $v_0$ and has no initial angular velocity $(\omega = 0)$.$1$. Since the ring is sliding,the kinetic friction force $f = \mu N = \mu Mg$ acts on it,which is the limiting friction.$2$. The friction force acts at the point of contact in a direction opposite to the velocity of the point of contact,which is opposite to the direction of motion of the ring.$3$. The friction force $f$ creates a torque $	au = f 	imes R$ about the centre of mass. Since the friction acts at the bottom point towards the left,the torque is in the clockwise direction,which causes an angular acceleration $\alpha$ in the clockwise sense.Therefore,all the given statements are correct.

$A$ ring of mass $M$ and radius $R$ sliding with a velocity $v_0$ suddenly enters a rough surface where the coefficient of friction is $\mu$,as shown in the figure. Choose the correct statement$(s)$.

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