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(C) The reaction uses $Zn-Hg/HCl$,which is the reagent for the Clemmensen reduction.Clemmensen reduction specifically reduces carbonyl groups (aldehyd

Vedclass · Accepted Answer

$3-$hydroxycyclopentane

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(C) The reaction uses $Zn-Hg/HCl$,which is the reagent for the Clemmensen reduction.Clemmensen reduction specifically reduces carbonyl groups (aldehydes and ketones) to methylene $(-CH_2-)$ groups.It does not affect other functional groups like hydroxyl $(-OH)$ groups under these acidic conditions.Therefore,the ketone group at position $1$ is reduced to a methylene group,while the hydroxyl group at position $3$ remains unchanged.The product is $3$-hydroxycyclopentane.

Predict the product of the following reaction:
$3$-hydroxycyclopentanone $\xrightarrow{Zn-Hg/HCl}$ product

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Predict the product of the following reaction:$3$-hydroxycyclopentanone $\xrightarrow{Zn-Hg/HCl}$ product