HBr reacts with CH_2=CH-OCH_3 at room tempera | vedclass

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(C) The reaction of $HBr$ with vinyl methyl ether $(CH_2=CH-OCH_3)$ is an electrophilic addition reaction. First,the $H^+$ ion from $HBr$ attacks the

Vedclass · Accepted Answer

$H_3C-CHBr-OCH_3$

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(C) The reaction of $HBr$ with vinyl methyl ether $(CH_2=CH-OCH_3)$ is an electrophilic addition reaction. First,the $H^+$ ion from $HBr$ attacks the double bond. Due to the resonance effect of the methoxy group $(-OCH_3)$,the electron density is higher on the terminal carbon atom $(CH_2)$. Thus,the protonation occurs at the terminal carbon to form a stable carbocation: $CH_3-CH^+-OCH_3$. This carbocation is stabilized by the lone pair of electrons on the oxygen atom. Finally,the bromide ion $(Br^-)$ attacks the carbocation to form the product $CH_3-CHBr-OCH_3$.

$HBr$ reacts with $CH_2=CH-OCH_3$ at room temperature to give

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