Excess $NaOH$ can dissolve
- A$Zn(OH)_2$
- B$Pb(OH)_2$
- C$Al(OH)_3$
- DAll
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Similar Questions
Boron compounds act as Lewis acids due to .....
Medium
View SolutionMatch the following:
List-$I$ (Group $13$ element) List-$II$ (Metallic radius,$pm$) $A$. $Al$ $I$. $135$ $B$. $Ga$ $II$. $143$ $C$. $In$ $III$. $170$ $D$. $Tl$ $IV$. $167$
The correct answer is:
| List-$I$ (Group $13$ element) | List-$II$ (Metallic radius,$pm$) |
|---|---|
| $A$. $Al$ | $I$. $135$ |
| $B$. $Ga$ | $II$. $143$ |
| $C$. $In$ | $III$. $170$ |
| $D$. $Tl$ | $IV$. $167$ |
The correct answer is:
The first ionization enthalpy values (in $kJ\, mol^{-1}$) of group $13$ elements are:
Element $B$ $Al$ $Ga$ $In$ $Tl$ Ionization Enthalpy $801$ $577$ $579$ $558$ $589$
How would you explain this deviation from the general trend?
| Element | $B$ | $Al$ | $Ga$ | $In$ | $Tl$ |
|---|---|---|---|---|---|
| Ionization Enthalpy | $801$ | $577$ | $579$ | $558$ | $589$ |
How would you explain this deviation from the general trend?
Difficult
View SolutionBoron halides behave as Lewis acids because of their
MediumAIPMT 1996
View SolutionThe correct formula of borax is $Na_2[B_4O_5(OH)_4] \cdot 8H_2O$. If the formula is represented as $Na_2[B_4O_5(OH)_x] \cdot yH_2O$, then the sum of $x$ and $y$ is:
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