Y xleftarrow{Delta ,, 205^circ C} CaSO_4 cdot | vedclass

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Question

(A) When $CaSO_4 \cdot 2H_2O$ (gypsum) is heated at $120^\circ C$ $(393 \ K)$,it loses $1.5$ molecules of water to form plaster of paris $(CaSO_4 \cdo

Vedclass · Accepted Answer

plaster of paris,dead burnt plaster

Vedclass · Answer

(A) When $CaSO_4 \cdot 2H_2O$ (gypsum) is heated at $120^\circ C$ $(393 \ K)$,it loses $1.5$ molecules of water to form plaster of paris $(CaSO_4 \cdot \frac{1}{2}H_2O)$.Thus,$X = CaSO_4 \cdot \frac{1}{2}H_2O$ (plaster of paris).When $CaSO_4 \cdot 2H_2O$ is heated at $205^\circ C$ $(478 \ K)$,it loses all its water of crystallization to form anhydrous calcium sulfate $(CaSO_4)$,which is known as dead burnt plaster.Thus,$Y = CaSO_4$ (dead burnt plaster).Therefore,$X$ is plaster of paris and $Y$ is dead burnt plaster.

$Y$ $\xleftarrow{\Delta ,\, 205^\circ C}$ $CaSO_4 \cdot 2H_2O$ $\xrightarrow{\Delta ,\, 120^\circ C}$ $X$. $X$ and $Y$ are respectively

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