Y xleftarrow[(ii),KOD, Br_2, Delta]{(i),NH_3, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is the Hofmann bromamide degradation,where the amide nitrogen is retained in the amine product.$1$. For $X$: Benzoic acid reacts with

Vedclass · Accepted Answer

$X$ is $	ext{deuterated aniline} (C_6H_5ND_2)$; $Y$ is $	ext{aniline} (C_6H_5NH_2)$

Vedclass · Answer

(A) The reaction is the Hofmann bromamide degradation,where the amide nitrogen is retained in the amine product.$1$. For $X$: Benzoic acid reacts with $ND_3$ and $\Delta$ to form benzamide $(C_6H_5COND_2)$. Subsequent reaction with $KOH$ and $Br_2$ yields $C_6H_5ND_2$ $(X)$,as the nitrogen atom of the amide is retained in the amine.$2$. For $Y$: Benzoic acid reacts with $NH_3$ and $\Delta$ to form benzamide $(C_6H_5CONH_2)$. Subsequent reaction with $KOD$ and $Br_2$ yields $C_6H_5NH_2$ $(Y)$,as the nitrogen atom of the amide is retained in the amine.Thus,$X$ is $C_6H_5ND_2$ and $Y$ is $C_6H_5NH_2$.

$Y \xleftarrow[(ii)\,KOD, Br_2, \Delta]{(i)\,NH_3, \Delta} \text{Benzoic acid}$ $\xrightarrow[(ii)\,KOH, Br_2, \Delta]{(i)\,ND_3, \Delta} X$
What are $X$ and $Y$?

Similar Questions

What is the major product of the following reaction?
$C_6H_5NO_2 \xrightarrow{Zn / NH_4Cl} \text{Product}$

What is the product formed when a primary amine reacts with an acid anhydride?

What is obtained upon the reduction of $t$-butyl isocyanide?

The compound which gives an oily nitrosoamine on reaction with nitrous acid at low temperature is:

The compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to give $Y (C_{13}H_{13}NO_{2}S)$ which is insoluble in alkali. The compound $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Y \xleftarrow[(ii)\,KOD, Br_2, \Delta]{(i)\,NH_3, \Delta} \text{Benzoic acid}$ $\xrightarrow[(ii)\,KOH, Br_2, \Delta]{(i)\,ND_3, \Delta} X$What are $X$ and $Y$?