2-chloropentane on halogenation with chlorine | vedclass

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Question

(B) The chlorination of $2-$chloropentane involves the abstraction of a hydrogen atom to form a free radical intermediate. In the formation of $2,3-$d

Vedclass · Accepted Answer

Trigonal planar

Vedclass · Answer

(B) The chlorination of $2-$chloropentane involves the abstraction of a hydrogen atom to form a free radical intermediate. In the formation of $2,3-$dichloropentane,the hydrogen is abstracted from the $C-3$ position. The resulting free radical at the $C-3$ carbon is $sp^2$ hybridized. An $sp^2$ hybridized carbon atom possesses a Trigonal planar geometry. Therefore,the correct option is $B$.

$2-$chloropentane on halogenation with chlorine gives $2,3-$dichloropentane. What will be the structure of the free radical species formed in the reaction?

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