C_6H_6 xrightarrow{CH_3COCl/AlCl_3} A xrighta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The reaction of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reac

Vedclass · Accepted Answer

Ethyl benzene

Vedclass · Answer

(B) $1$. The reaction of benzene $(C_6H_6)$ with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction. This produces acetophenone $(C_6H_5COCH_3)$ as product $A$.$2$. The reaction of acetophenone $(C_6H_5COCH_3)$ with $Zn-Hg/HCl$ is a Clemmensen reduction,which reduces the carbonyl group $(>C=O)$ to a methylene group $(-CH_2-)$.$3$. The reduction of acetophenone yields ethyl benzene $(C_6H_5CH_2CH_3)$ as the final product $B$.

$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} A$ $\xrightarrow{Zn-Hg/HCl} B$
The end product in the above sequence is:

Similar Questions

Hybridised states of carbon in graphite and diamond are respectively

Benzene cannot undergo

The reaction of benzene with a mixture of concentrated $HNO_3$ and concentrated $H_2SO_4$,followed by treatment with $Cl_2 / FeCl_3$,gives:

The molecular formula of hexachlorobenzene is

$o, p-$ directing groups are mostly

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} A$ $\xrightarrow{Zn-Hg/HCl} B$ The end product in the above sequence is: