A 5% , w/v solution of cane sugar is isotonic | vedclass

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(C) Two solutions are isotonic if they have the same osmotic pressure,which implies they have the same molar concentration $(C_1 = C_2)$.For a $5\% \,

Vedclass · Accepted Answer

$68.4$

Vedclass · Answer

(C) Two solutions are isotonic if they have the same osmotic pressure,which implies they have the same molar concentration $(C_1 = C_2)$.For a $5\% \, w/v$ solution of cane sugar $(C_{12}H_{22}O_{11})$,the mass of solute is $5 \ g$ in $100 \ mL$ of solution.Molar mass of cane sugar $= 342 \ g/mol$.Molarity $(C_1)$ $= \frac{5 \ g}{342 \ g/mol} 	imes \frac{1000 \ mL}{100 \ mL} = \frac{50}{342} \ M$.For a $1\% \, w/v$ solution of substance $X$,the mass of solute is $1 \ g$ in $100 \ mL$ of solution.Let the molar mass of $X$ be $M$.Molarity $(C_2)$ $= \frac{1 \ g}{M \ g/mol} 	imes \frac{1000 \ mL}{100 \ mL} = \frac{10}{M} \ M$.Since the solutions are isotonic,$C_1 = C_2$:$\frac{50}{342} = \frac{10}{M}$$M = \frac{10 	imes 342}{50} = \frac{342}{5} = 68.4 \ g/mol$.

$A$ $5\% \, w/v$ solution of cane sugar is isotonic with a $1\% \, w/v$ solution of substance $X$. The molecular weight of $X$ is:

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