A 12,m deep well with internal diameter 3.5,m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The volume of the earth dug out is equal to the volume of the cylindrical well.Radius of the well $r = \frac{3.5}{2} = 1.75\,m$.Depth of the well

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) The volume of the earth dug out is equal to the volume of the cylindrical well.Radius of the well $r = \frac{3.5}{2} = 1.75\,m$.Depth of the well $h = 12\,m$.Volume of earth = $\pi r^2 h = \frac{22}{7} 	imes 1.75 	imes 1.75 	imes 12 = 115.5\,m^3$.Let the height of the platform be $H$.The volume of the platform is equal to the volume of the earth dug out.Volume of platform = $	ext{Length} 	imes 	ext{Width} 	imes 	ext{Height} = 10.5 	imes 8.8 	imes H = 92.4 	imes H$.Equating the volumes: $92.4 	imes H = 115.5$.$H = \frac{115.5}{92.4} = 1.25\,m$.

$A$ $12\,m$ deep well with internal diameter $3.5\,m$ is dug. The earth taken out from it is spread evenly to form a platform of dimensions $10.5\,m \times 8.8\,m$. Determine the height of the platform in meters. (in $.25$)

Similar Questions

If surface area and volume of a sphere are $S$ and $V$,respectively,then the value of $\frac{S^{3}}{V^{2}}$ is......$\pi$.

If a sphere of radius $r$ is divided into $4$ identical parts,then the total surface area of the $4$ parts is

The radius of a cylinder is $10\, cm$ and its height is $4\, cm$. The value of $x$ (in $cm$) that may be added either to the radius or to the height to get the same increase in the volume of the cylinder is:

The material of a cone is converted into the shape of a cylinder of equal radius. If the height of the cylinder is $5\, cm$,the height of the cone is........$cm$.

$2$ cubes have volumes in the ratio $1:27$. The ratio of the area of the face of one to that of the other is

Vedclass Test Series

Exam Paper Generator

Online Exam Module