A 100 , Omega resistance,a 0.1 , mu text{F} c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given:Resistance $R = 100 \, \Omega$Capacitance $C = 0.1 \, \mu 	ext{F} = 0.1 	imes 10^{-6} \, 	ext{F} = 10^{-7} \, 	ext{F}$Resonant frequency

Vedclass · Accepted Answer

$70.3$

Vedclass · Answer

(D) Given:Resistance $R = 100 \, \Omega$Capacitance $C = 0.1 \, \mu 	ext{F} = 0.1 	imes 10^{-6} \, 	ext{F} = 10^{-7} \, 	ext{F}$Resonant frequency $f_0 = 60 \, 	ext{Hz}$At resonance,the inductive reactance equals the capacitive reactance:$X_L = X_C$$2 \pi f_0 L = \frac{1}{2 \pi f_0 C}$Rearranging for inductance $L$:$L = \frac{1}{4 \pi^2 f_0^2 C}$Substituting the values:$L = \frac{1}{4 	imes (3.14)^2 	imes (60)^2 	imes 10^{-7}}$$L = \frac{1}{4 	imes 9.8596 	imes 3600 	imes 10^{-7}}$$L = \frac{1}{141978.24 	imes 10^{-7}}$$L = \frac{1}{0.0141978}$$L \approx 70.43 \, 	ext{H}$Rounding to the nearest provided option,the correct value is $70.3 \, 	ext{H}$.

Similar Questions

The plot given below is of the average power delivered to an $LRC$ circuit versus frequency. The quality factor of the circuit is

The $LC$ parallel resonant circuit:

$A$ series $L-C-R$ circuit containing a resistance $R$ has angular frequency $\omega$. At resonance,the voltages across the resistance and the inductor are $V_R$ and $V_L$ respectively. The value of the capacitance is:

For the series $LCR$ circuit shown in the figure,what is the resonance angular frequency and the amplitude of the current at the resonating frequency? The source voltage is given as $220 \, V$ ($RMS$ value).

The frequencies at which the current amplitude in an $LCR$ series circuit becomes $\frac{1}{\sqrt{2}}$ times its maximum value are $212\,rad\,s^{-1}$ and $232\,rad\,s^{-1}$. The value of resistance in the circuit is $R = 5\,\Omega$. The self-inductance in the circuit is $.........\,mH$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module