An NCC parade is moving at a uniform speed of | vedclass

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(A) The time taken by the mango to reach the ground is given by the formula for free fall: $t = \sqrt{\frac{2h}{g}}$.Substituting the given values $h

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The time taken by the mango to reach the ground is given by the formula for free fall: $t = \sqrt{\frac{2h}{g}}$.Substituting the given values $h = 19.6\,m$ and $g = 9.8\,m/s^2$:$t = \sqrt{\frac{2 	imes 19.6}{9.8}} = \sqrt{4} = 2\,s$.The speed of the parade is $v = 9\,km/h$. Converting this to $m/s$:$v = 9 	imes \frac{5}{18} = 2.5\,m/s$.The distance covered by the cadet in time $t$ is $d = v 	imes t$.$d = 2.5 	imes 2 = 5\,m$.Therefore,the cadet must be $5\,m$ away from the tree at the instant the mango is dropped to catch it.

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