(B) The formula for the shunt resistance $S$ required to convert a galvanometer of resistance $G$ into an ammeter of range $I$ is given by $S = \frac{

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(B) The formula for the shunt resistance $S$ required to convert a galvanometer of resistance $G$ into an ammeter of range $I$ is given by $S = \frac{I_g G}{I - I_g}$.Given:Galvanometer resistance $G = 50\, \Omega$.Full-scale deflection current $I_g = 0.01\, A$.Desired range of ammeter $I = 10\, A$.Substituting the values into the formula:$S = \frac{0.01 \times 50}{10 - 0.01}$$S = \frac{0.5}{9.99}$$S \approx 0.05\, \Omega$.Thus,the shunt resistance is $0.05\, \Omega$.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Medium

$A$ $50\, \Omega$ galvanometer gets full-scale deflection when a current of $0.01\, A$ passes through the coil. When it is converted to a $10\, A$ ammeter,the shunt resistance is ........... $\Omega$.

A
$0.01$
B
$0.05$
C
$2000$
D
$5000$

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Class 12

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

$A$ small cylindrical soft iron piece is kept in a galvanometer so that

Easy

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When a resistance of $200\Omega$ is connected in series with a galvanometer of resistance $G$, its range is $V$. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is (in $\Omega$)

DifficultMHT CET 2026

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$A$ galvanometer with $30$ divisions has a current sensitivity of $20 \, \mu A/division$. Its resistance is $25 \, \Omega$. How will you convert it into an ammeter to measure $1 \, A$ current?

Medium

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$A$ galvanometer coil has a resistance of $50 \Omega$ and the meter shows full scale deflection for a current of $5 \text{ mA}$. This galvanometer is converted into a voltmeter of range $0-20 \text{ V}$ by connecting:

MediumKCET 2016

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To convert a galvanometer into an ammeter,we connect . . . . . . .

EasyGUJCET 2007

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$A$ $50\, \Omega$ galvanometer gets full-scale deflection when a current of $0.01\, A$ passes through the coil. When it is converted to a $10\, A$ ammeter,the shunt resistance is ........... $\Omega$.

Similar Questions

$A$ small cylindrical soft iron piece is kept in a galvanometer so that

When a resistance of $200\Omega$ is connected in series with a galvanometer of resistance $G$, its range is $V$. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is (in $\Omega$)

$A$ galvanometer with $30$ divisions has a current sensitivity of $20 \, \mu A/division$. Its resistance is $25 \, \Omega$. How will you convert it into an ammeter to measure $1 \, A$ current?

$A$ galvanometer coil has a resistance of $50 \Omega$ and the meter shows full scale deflection for a current of $5 \text{ mA}$. This galvanometer is converted into a voltmeter of range $0-20 \text{ V}$ by connecting:

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