A ball is dropped from height h on a plane. I | vedclass

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(A) When a ball is dropped from a height $h$,its velocity just before the first impact is $v_0 = \sqrt{2gh}$.After the first impact with a coefficient

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$e^4h$

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(A) When a ball is dropped from a height $h$,its velocity just before the first impact is $v_0 = \sqrt{2gh}$.After the first impact with a coefficient of restitution $e$,the velocity becomes $v_1 = ev_0 = e\sqrt{2gh}$.The height reached after the first jump is $h_1 = \frac{v_1^2}{2g} = e^2h$.After the second impact,the velocity becomes $v_2 = ev_1 = e^2\sqrt{2gh}$.The height reached after the second jump is $h_2 = \frac{v_2^2}{2g} = e^4h$.In general,the height attained after $n$ jumps is given by $h_n = e^{2n}h$.For $n = 2$,the height is $h_2 = e^{2(2)}h = e^4h$.

$A$ ball is dropped from height $h$ on a plane. If the coefficient of restitution of the plane is $e$ and the ball hits the ground two times,the height up to which it reaches after two jumps will be:

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