$A$ ball of lead,$4\, cm$ in diameter,is covered with gold. If the volume of the gold and lead are equal,then the thickness of gold is approximately (in $cm$).
$[$ Given $\sqrt[3]{2} = 1.259 ]$

  • A
    $5.038$
  • B
    $5.190$
  • C
    $1.038$
  • D
    $0.518$

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