A ball with a speed of 9, m/s collides with a | vedclass

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(D) Let the mass of each ball be $m$. The initial velocity of ball $A$ is $u_1 = 9\, m/s$ and ball $B$ is $u_2 = 0$.After the collision,let the veloci

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$1$

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(D) Let the mass of each ball be $m$. The initial velocity of ball $A$ is $u_1 = 9\, m/s$ and ball $B$ is $u_2 = 0$.After the collision,let the velocities of balls $A$ and $B$ be $v_1$ and $v_2$ respectively,both at an angle of $30^{\circ}$ with the original direction.According to the law of conservation of linear momentum along the $y$-axis (perpendicular to the initial direction of motion):$\sum P_{iy} = \sum P_{fy}$$0 = m v_1 \sin 30^{\circ} - m v_2 \sin 30^{\circ}$Since the masses are identical and $\sin 30^{\circ} 
eq 0$,we get:$v_1 \sin 30^{\circ} = v_2 \sin 30^{\circ}$$v_1 = v_2$Therefore,the ratio of the velocities $v_1 : v_2$ is $1 : 1$.Thus,$x = 1$.

$A$ ball with a speed of $9\, m/s$ collides with another identical ball at rest. After the collision,the direction of each ball makes an angle of $30^{\circ}$ with the original direction. The ratio of velocities of the balls after collision is $x : y$ where $x$ is........

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