A balloon has 2 ,g of air. A small hole is pi | vedclass

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(B) The average force $F$ exerted on the balloon due to the escaping air is given by the rate of change of momentum,which is $F = v \frac{dm}{dt}$.Her

Vedclass · Accepted Answer

$0.0032$

Vedclass · Answer

(B) The average force $F$ exerted on the balloon due to the escaping air is given by the rate of change of momentum,which is $F = v \frac{dm}{dt}$.Here,the velocity of the air $v = 4 \,m/s$.The total mass of air $m = 2 \,g = 0.002 \,kg$.The time taken for the air to escape $dt = 2.5 \,s$.Substituting these values into the formula:$F = 4 	imes \left( \frac{0.002 \,kg}{2.5 \,s} ight)$$F = 4 	imes 0.0008 \,N$$F = 0.0032 \,N$.Therefore,the average force acting on the balloon is $0.0032 \,N$.

$A$ balloon has $2 \,g$ of air. $A$ small hole is pierced into it. The air comes out with a velocity of $4 \,m/s$. If the balloon shrinks completely in $2.5 \,s$,the average force acting on the balloon is ..........$N$.

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