A bar magnet is oscillating in the Earth's ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The time period of a bar magnet oscillating in a magnetic field is given by $T = 2\pi \sqrt{\frac{I}{MB}}$,where $I$ is the moment of inertia,$M$

Vedclass · Accepted Answer

Motion remains $S.H.M.$ with time period $= 2T$

Vedclass · Answer

(A) The time period of a bar magnet oscillating in a magnetic field is given by $T = 2\pi \sqrt{\frac{I}{MB}}$,where $I$ is the moment of inertia,$M$ is the magnetic moment,and $B$ is the magnetic field.For a bar magnet of mass $m$ and length $l$,the moment of inertia is $I = \frac{ml^2}{12}$.Substituting this into the formula,we get $T = 2\pi \sqrt{\frac{ml^2}{12MB}}$.This shows that $T \propto \sqrt{m}$.If the mass $m$ is quadrupled $(m' = 4m)$,the new time period $T'$ becomes $T' = 2\pi \sqrt{\frac{4ml^2}{12MB}} = 2 	imes (2\pi \sqrt{\frac{ml^2}{12MB}}) = 2T$.The motion remains $S.H.M.$ because the restoring torque $	au = -MB \sin 	heta \approx -MB 	heta$ for small oscillations.

$A$ bar magnet is oscillating in the Earth's magnetic field with a period $T$. What happens to its period and motion if its mass is quadrupled?

Similar Questions

$A$ bar magnet is placed on a table along the east-west direction in the Earth's magnetic field. The number of neutral points,where the magnetic field is zero,is

$A$ magnetic needle suspended horizontally by an unspun silk fibre,oscillates in the horizontal plane because of the restoring force originating mainly from

The time period of a freely suspended magnet is $2 \ s$. If it is broken in length into two equal parts and one part is suspended in the same way,then its time period will be.....$s$.

Two tangent galvanometer coils of the same radius are connected in series. The current flowing produces deflections of $60^o$ and $45^o$. The ratio of the number of turns in the coils is:

Two bar magnets $A$ and $B$ are geometrically similar but the magnetic moment of $A$ is twice that of $B$. $T_1$ is the time period of oscillation when their like poles are kept together. When unlike poles are kept together,the time period of oscillation is $T_2$. The ratio $T_1: T_2$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module