A basket contains 5 apples and 7 oranges,and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $B_1$ be the first basket and $B_2$ be the second basket.Total fruits in $B_1 = 5 + 7 = 12$.Total fruits in $B_2 = 4 + 8 = 12$.Probability of

Vedclass · Accepted Answer

$\frac{76}{144}$

Vedclass · Answer

(D) Let $B_1$ be the first basket and $B_2$ be the second basket.Total fruits in $B_1 = 5 + 7 = 12$.Total fruits in $B_2 = 4 + 8 = 12$.Probability of picking an apple from $B_1 = \frac{5}{12}$.Probability of picking an apple from $B_2 = \frac{4}{12}$.Probability of picking an orange from $B_1 = \frac{7}{12}$.Probability of picking an orange from $B_2 = \frac{8}{12}$.Since the events are independent,the probability that both are apples is $\frac{5}{12} 	imes \frac{4}{12} = \frac{20}{144}$.The probability that both are oranges is $\frac{7}{12} 	imes \frac{8}{12} = \frac{56}{144}$.Since these events are mutually exclusive,the total probability is $\frac{20}{144} + \frac{56}{144} = \frac{76}{144}$.

$A$ basket contains $5$ apples and $7$ oranges,and another basket contains $4$ apples and $8$ oranges. One fruit is picked out from each basket. Find the probability that the fruits are both apples or both oranges.

Similar Questions

For the two events $A$ and $B$,$P(A) = 0.38$ and $P(B) = 0.41$. What is the value of $P(\text{not } A)$?

$A$ mapping is selected at random from the set of all the mappings of the set $A = \{1, 2, ..., n\}$ into itself. The probability that the mapping selected is an injection is

$2$ dice are thrown. Find the probability of getting $6$ as the product.

The probability of drawing a white ball from a bag containing $3$ black balls and $4$ white balls is:

$A$ bag contains $7$ black and $5$ white balls. $A$ ball is drawn out and replaced in the bag. Then a ball is drawn again. What is the probability that both balls were black?

Vedclass Test Series

Exam Paper Generator

Online Exam Module