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(D) The angle of incidence $i$ is the angle between the incident ray and the normal. From the figure,the angle between the ray and the surface is $33^

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The intensity gradually reduces to zero and then again increases.

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(D) The angle of incidence $i$ is the angle between the incident ray and the normal. From the figure,the angle between the ray and the surface is $33^\circ$. Thus,the angle of incidence $i = 90^\circ - 33^\circ = 57^\circ$.Brewster's law states that the polarising angle $i_p$ is given by $	an(i_p) = \mu$. For glass with $\mu = 1.54$,$i_p = 	an^{-1}(1.54) \approx 57^\circ$.Since the angle of incidence is equal to the polarising angle,the reflected light is completely plane-polarised.When plane-polarised light is passed through a rotating Nicol prism (acting as an analyser),the intensity $I$ follows Malus' Law: $I = I_0 \cos^2(	heta)$,where $	heta$ is the angle between the transmission axis of the prism and the plane of polarisation.As the prism rotates,the intensity varies from a maximum to zero (when the transmission axis is perpendicular to the plane of polarisation) and then increases again. Thus,the intensity gradually reduces to zero and then again increases.

$A$ beam of light $AO$ is incident on a glass slab $(\mu = 1.54)$ in a direction as shown in the figure. The reflected ray $OB$ is passed through a Nicol prism. On viewing through the Nicol prism,we find on rotating the prism that:

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