(B) The normal force $N$ acting on the block is given by $N = mg \cos \theta$.Given: $m = 1 \ kg$,$g = 10 \ m/s^2$,$\theta = 60^{\circ}$,and $\mu_s =

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(B) The normal force $N$ acting on the block is given by $N = mg \cos \theta$.Given: $m = 1 \ kg$,$g = 10 \ m/s^2$,$\theta = 60^{\circ}$,and $\mu_s = 0.1$.$N = 1 \times 10 \times \cos(60^{\circ}) = 10 \times 0.5 = 5 \ N$.The frictional force $f$ is given by $f = \mu_s N$.$f = 0.1 \times 5 = 0.5 \ N$.The work done against the frictional force over a distance $d = 10 \ m$ is:$W = f \times d = 0.5 \times 10 = 5 \ J$.

Class 11 Physics Newton's Laws of Motion and Friction Motion (or rest) on Rough Inclined Surface

Difficult

$A$ block of mass $1 \ kg$ is pushed up a surface inclined to the horizontal at an angle of $60^{\circ}$ by a force of $10 \ N$ parallel to the inclined surface as shown in the figure. When the block is pushed up by $10 \ m$ along the inclined surface,the work done against the frictional force is: $\left[g=10 \ m/s^2, \mu_s = 0.1\right]$

JEE MAIN 2024 All JEE MAIN

A
$5 \sqrt{3} \ J$
B
$5 \ J$
C
$5 \times 10^3 \ J$
D
$10 \ J$

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Class 11

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Newton's Laws of Motion and Friction

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Motion (or rest) on Rough Inclined Surface

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$A$ block of mass $4 \ kg$ is at rest on a rough inclined plane making an angle of $\theta$ with the horizontal. The coefficient of static friction between the block and the plane is $0.5$ and the frictional force on the block is $14.14 \ N$. Find the value of $\theta$. (in $^{\circ}$)

MediumTS EAMCET 2020

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$A$ uniform chain of length $L$ hangs partly from a table and is kept in equilibrium by friction. If the maximum length of the chain that can hang without slipping is $l$,then the coefficient of friction between the table and the chain is:

Easy

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$A$ block of mass $0.1 \, kg$ is held against a wall by applying a horizontal force of $5 \, N$ on the block. If the coefficient of friction between the block and the wall is $0.5$,the magnitude of the frictional force acting on the block is ........ $N$.

MediumIIT 1994

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The minimum force required to start pushing a body up a rough (frictional coefficient $\mu$) inclined plane is $F_{1}$,while the minimum force needed to prevent it from sliding down is $F_{2}$. If the inclined plane makes an angle $\theta$ with the horizontal such that $\tan \theta = 2\mu$,then the ratio $\frac{F_{1}}{F_{2}}$ is:

DifficultAIEEE 2011

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$A$ body of mass $10\, kg$ is lying on a rough plane inclined at an angle of $30^\circ$ to the horizontal,and the coefficient of friction is $0.5$. The minimum force required to pull the body up the plane is ........ $N$.

Medium

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$A$ block of mass $4 \ kg$ is at rest on a rough inclined plane making an angle of $\theta$ with the horizontal. The coefficient of static friction between the block and the plane is $0.5$ and the frictional force on the block is $14.14 \ N$. Find the value of $\theta$. (in $^{\circ}$)

$A$ uniform chain of length $L$ hangs partly from a table and is kept in equilibrium by friction. If the maximum length of the chain that can hang without slipping is $l$,then the coefficient of friction between the table and the chain is:

$A$ block of mass $0.1 \, kg$ is held against a wall by applying a horizontal force of $5 \, N$ on the block. If the coefficient of friction between the block and the wall is $0.5$,the magnitude of the frictional force acting on the block is ........ $N$.

$A$ body of mass $10\, kg$ is lying on a rough plane inclined at an angle of $30^\circ$ to the horizontal,and the coefficient of friction is $0.5$. The minimum force required to pull the body up the plane is ........ $N$.

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