A body has -80 mu C of charge. The number of | vedclass

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(C) The quantization of charge is given by the formula $Q = Ne$,where $Q$ is the total charge,$N$ is the number of electrons,and $e$ is the elementary

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$5 	imes 10^{14}$

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(C) The quantization of charge is given by the formula $Q = Ne$,where $Q$ is the total charge,$N$ is the number of electrons,and $e$ is the elementary charge $(e \approx 1.6 	imes 10^{-19} \ C)$.Given: $Q = 80 \ \mu C = 80 	imes 10^{-6} \ C$.Using the formula $N = \frac{Q}{e}$:$N = \frac{80 	imes 10^{-6}}{1.6 	imes 10^{-19}}$$N = \frac{80}{1.6} 	imes 10^{-6 - (-19)}$$N = 50 	imes 10^{13} = 5 	imes 10^{14}$.Therefore,the number of additional electrons is $5 	imes 10^{14}$.

$A$ body has $-80 \ \mu C$ of charge. The number of additional electrons in it will be:

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