A body of mass m is moving in a circle of rad | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The force acting on the body is the centripetal force,which is always directed towards the center of the circular path.The displacement of the bod

Vedclass · Accepted Answer

zero

Vedclass · Answer

(B) The force acting on the body is the centripetal force,which is always directed towards the center of the circular path.The displacement of the body at any instant is along the tangent to the circle at that point.Since the radius (and thus the centripetal force) is always perpendicular to the tangent (displacement),the angle $	heta$ between the force vector $\vec{F}$ and the displacement vector $d\vec{s}$ is always $90^{\circ}$.The work done $W$ is given by the dot product of force and displacement: $W = \int \vec{F} \cdot d\vec{s} = \int F \cos(90^{\circ}) ds$.Since $\cos(90^{\circ}) = 0$,the work done by the centripetal force is always zero,regardless of the distance traveled along the circumference.

$A$ body of mass $m$ is moving in a circle of radius $r$ with a constant speed $u$. The force on the body is $mv^2/r$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?

Similar Questions

$A$ force $\vec F = 2\hat i - 3\hat j + 7\hat k \text{ (N)}$ acts on a particle which undergoes a displacement of $\vec S = 7\hat i + 3\hat j - 2\hat k \text{ (m)}$. Calculate the work done by the force in $J$.

If a person is pushing a box inside a moving train,the work done in the frame of the earth will be: (where $\vec{s}$ is the displacement of the box in the train and $\vec{s}_0$ is the displacement of the train relative to the ground)

$A$ cyclist comes to a skidding stop in $10 \; m$. During this process,the force on the cycle due to the road is $200 \; N$ and is directly opposed to the motion.
$(a)$ How much work does the road do on the cycle?
$(b)$ How much work does the cycle do on the road?

$A$ force $\vec F = 6\hat i + 2\hat j - 3\hat k$ acts on a particle,causing a displacement $\vec d = 2\hat i - 3\hat j + c\hat k$. If the work done during this process is zero,find the value of $c$.

At time $t=0$,a particle starts moving along the $x$-axis. If its kinetic energy increases uniformly with time $t$,the net force acting on it must be proportional to

Vedclass Test Series

Exam Paper Generator

Online Exam Module