A body weighs 500 , N on the surface of the e | vedclass

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(B) The weight of a body on the surface of the earth is given by $W = mg = 500 \, N$.The acceleration due to gravity at a depth $d$ below the surface

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$250$

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(B) The weight of a body on the surface of the earth is given by $W = mg = 500 \, N$.The acceleration due to gravity at a depth $d$ below the surface of the earth is given by the formula $g' = g(1 - \frac{d}{R})$,where $R$ is the radius of the earth.Given that the body is halfway below the surface,the depth $d = \frac{R}{2}$.Substituting this value into the formula:$g' = g(1 - \frac{R/2}{R}) = g(1 - \frac{1}{2}) = \frac{g}{2}$.Therefore,the weight at depth $d$ is $W' = mg' = m(\frac{g}{2}) = \frac{mg}{2}$.Substituting $mg = 500 \, N$:$W' = \frac{500}{2} = 250 \, N$.

$A$ body weighs $500 \, N$ on the surface of the earth. How much would it weigh halfway below the surface of the earth (in $, N$)?

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