A bottle full of whisky contains 50 % alcohol | vedclass

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Question

(B) Using the rule of alligation,we compare the concentrations of the two solutions to the final mixture concentration:Concentration of first solution

Vedclass · Accepted Answer

$\frac{3}{4}$

Vedclass · Answer

(B) Using the rule of alligation,we compare the concentrations of the two solutions to the final mixture concentration:Concentration of first solution = $50 \%$Concentration of second solution = $18 \%$Mean concentration of the mixture = $26 \%$Applying the alligation rule:Ratio of (first solution) : (second solution) = $(26 - 18) : (50 - 26)$Ratio = $8 : 24 = 1 : 3$This means that for every $1$ part of the original whisky remaining,$3$ parts of the new solution were added.Therefore,the quantity of whisky replaced is $\frac{3}{1 + 3} = \frac{3}{4}$.

$A$ bottle full of whisky contains $50 \%$ alcohol. $A$ part of this whisky is replaced by another containing $18 \%$ alcohol and the percentage of alcohol was found to be $26 \%$. The quantity of whisky replaced is

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