A box contains 6 white and 8 red balls. Two b | vedclass

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(C) The total number of ways to draw $2$ balls from a total of $(6 + 8) = 14$ balls is given by the combination formula ${}^{14}C_{2} = \frac{14 	ime

Vedclass · Accepted Answer

$\frac{48}{91}$

Vedclass · Answer

(C) The total number of ways to draw $2$ balls from a total of $(6 + 8) = 14$ balls is given by the combination formula ${}^{14}C_{2} = \frac{14 	imes 13}{2 	imes 1} = 91$.The number of ways to choose $1$ white ball from $6$ white balls is ${}^{6}C_{1} = 6$.The number of ways to choose $1$ red ball from $8$ red balls is ${}^{8}C_{1} = 8$.The number of favorable outcomes where one ball is white and the other is red is ${}^{6}C_{1} 	imes {}^{8}C_{1} = 6 	imes 8 = 48$.Therefore,the probability is $\frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{48}{91}$.

$A$ box contains $6$ white and $8$ red balls. Two balls are drawn at random in succession. What is the probability that one of them is white and the other red?

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