A boy started from his house by bicycle at 10 | vedclass

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(C) The boy started at $10:00\, a.m.$ and was caught at $1:30\, p.m.$ The total time taken by the boy is $3\, hours\, 30\, minutes = 3.5\, hours = \fr

Vedclass · Accepted Answer

$18\frac{2}{3}$

Vedclass · Answer

(C) The boy started at $10:00\, a.m.$ and was caught at $1:30\, p.m.$ The total time taken by the boy is $3\, hours\, 30\, minutes = 3.5\, hours = \frac{7}{2}\, hours$.Distance covered by the boy $= 	ext{Speed} 	imes 	ext{Time} = 12\, km/hr 	imes \frac{7}{2}\, hr = 42\, km$.The elder brother started $1\, hr\, 15\, mins$ later,which is $1.25\, hours = \frac{5}{4}\, hours$ after $10:00\, a.m.$The time taken by the scooter to cover the same distance is $\frac{7}{2} - \frac{5}{4} = \frac{14-5}{4} = \frac{9}{4}\, hours$.Let the speed of the scooter be $x\, km/hr$.Since distance is the same,$x 	imes \frac{9}{4} = 42$.$x = \frac{42 	imes 4}{9} = \frac{14 	imes 4}{3} = \frac{56}{3} = 18\frac{2}{3}\, km/hr$.

$A$ boy started from his house by bicycle at $10:00\, a.m.$ at a speed of $12\, km/hr$. His elder brother started after $1\, hr\, 15\, mins$ by scooter along the same path and caught him at $1:30\, p.m.$ The speed of the scooter will be (in $km/hr$):

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