$A$ capacitor of capacity $C_1$ is charged up to $V$ volt and then connected to an uncharged capacitor of capacity $C_2$. The final potential difference across each will be:

  • A
    $\frac{C_2 V}{C_1 + C_2}$
  • B
    $\left( 1 + \frac{C_2}{C_1} \right) V$
  • C
    $\frac{C_1 V}{C_1 + C_2}$
  • D
    $\left( 1 - \frac{C_2}{C_1} \right) V$

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