$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be
- A$M$
- B$M/2$
- C$2M$
- D$4M$
Explore More
Similar Questions
If we dip capillary tubes of different radii $r_n$ in water and the water rises to different heights $h_n$ in them, then $(n = 1, 2, 3, ...)$
$A$ capillary tube of radius $R$ is dipped in water,and water rises to a height $H$. The mass of water in the capillary tube is $M$. If a capillary tube of half the radius is dipped in water,what will be the mass of the water in the capillary tube?
Medium
View SolutionWhat is capillary action? Derive the formula for the rise of liquid in a capillary tube immersed vertically in a liquid.
Difficult
View SolutionIf a capillary experiment is performed in a vacuum,what happens to the liquid level in the capillary tube?
Easy
View SolutionIn a capillary tube of area of cross-section '$a$',water rises to a height '$h$'. To what height will water rise in a capillary tube of area of cross-section $4a$?
DifficultMHT CET 2026
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo