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(B) The car is undergoing non-uniform circular motion.There are two components of acceleration:$1$. Tangential acceleration $(a_t)$: This is the rate

Vedclass · Accepted Answer

$2.7$

Vedclass · Answer

(B) The car is undergoing non-uniform circular motion.There are two components of acceleration:$1$. Tangential acceleration $(a_t)$: This is the rate of change of speed,given as $a_t = 2 \ m/s^2$.$2$. Centripetal acceleration $(a_c)$: This is directed towards the center of the circular path,given by $a_c = \frac{v^2}{r}$.Substituting the values: $a_c = \frac{(30)^2}{500} = \frac{900}{500} = 1.8 \ m/s^2$.The net acceleration $(a)$ is the vector sum of these two perpendicular components:$a = \sqrt{a_t^2 + a_c^2} = \sqrt{(2)^2 + (1.8)^2} = \sqrt{4 + 3.24} = \sqrt{7.24} \approx 2.69 \ m/s^2$.Rounding to one decimal place,the acceleration is $2.7 \ m/s^2$.

$A$ car is moving with a speed of $30 \ m/s$ on a circular path of radius $500 \ m$. Its speed is increasing at the rate of $2 \ m/s^2$. What is the acceleration of the car in $m/s^2$?

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