A car runs at a constant speed on a circular | vedclass

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Question

(C) The distance traveled in one complete circular lap is equal to the circumference of the track,which is $2\pi r$.Given $r = 100\,m$ and time $t = 6

Vedclass · Accepted Answer

$0\,m/s, 10\,m/s$

Vedclass · Answer

(C) The distance traveled in one complete circular lap is equal to the circumference of the track,which is $2\pi r$.Given $r = 100\,m$ and time $t = 62.8\,s$.Average speed is defined as the total distance divided by the total time:$	ext{Average speed} = \frac{2\pi r}{t} = \frac{2 	imes 3.14 	imes 100}{62.8} = \frac{628}{62.8} = 10\,m/s$.Since the car completes one full lap,the final position is the same as the initial position.Therefore,the net displacement is $0\,m$.Average velocity is defined as the net displacement divided by the total time:$	ext{Average velocity} = \frac{	ext{net displacement}}{t} = \frac{0}{62.8} = 0\,m/s$.Thus,the average velocity is $0\,m/s$ and the average speed is $10\,m/s$.

$A$ car runs at a constant speed on a circular track of radius $100\,m$,taking $62.8\,s$ for every circular lap. The average velocity and average speed for each circular lap respectively are:

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