A car starts from A for B travelling at 20 , | vedclass

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(C) Let the distance between $A$ and $B$ be $d \, km$.Time taken by the first car to cover the distance $d$ is $t_1 = \frac{d}{20} \, hours$.Time take

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$240$

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(C) Let the distance between $A$ and $B$ be $d \, km$.Time taken by the first car to cover the distance $d$ is $t_1 = \frac{d}{20} \, hours$.Time taken by the second car to cover the distance $d$ is $t_2 = \frac{d}{30} \, hours$.The second car starts $1.5 \, hours$ later and reaches $2.5 \, hours$ earlier,so the difference in time is $t_1 - t_2 = 1.5 + 2.5 = 4 \, hours$.Substituting the values: $\frac{d}{20} - \frac{d}{30} = 4$.Taking the $LCM$ of $20$ and $30$,which is $60$: $\frac{3d - 2d}{60} = 4$.$\frac{d}{60} = 4$.$d = 240 \, km$.Thus,the distance from $A$ to $B$ is $240 \, km$.

$A$ car starts from $A$ for $B$ travelling at $20 \, km/h$. $1 \frac{1}{2} \, hours$ later,another car starts from $A$ and,travelling at the rate of $30 \, km/h$,reaches $B$ $2 \frac{1}{2} \, hours$ before the first car. Find the distance from $A$ to $B$ (in $km$).

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