A car starts from rest and accelerates at 5 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) At $t=4 \, s$,the velocity of the car (and thus the ball) in the horizontal direction is $v_x = u + at = 0 + 5 	imes 4 = 20 \, m/s$. After the ba

Vedclass · Accepted Answer

$20 \sqrt{2} \, m/s, 10 \, m/s^{2}$

Vedclass · Answer

(D) At $t=4 \, s$,the velocity of the car (and thus the ball) in the horizontal direction is $v_x = u + at = 0 + 5 	imes 4 = 20 \, m/s$. After the ball is dropped,it is only under the influence of gravity. At $t=6 \, s$,the time elapsed since the ball was dropped is $\Delta t = 6 - 4 = 2 \, s$. The horizontal velocity remains constant: $v_x = 20 \, m/s$. The vertical velocity at $\Delta t = 2 \, s$ is $v_y = u_y + g \Delta t = 0 + 10 	imes 2 = 20 \, m/s$. The resultant velocity is $v = \sqrt{v_x^2 + v_y^2} = \sqrt{20^2 + 20^2} = 20 \sqrt{2} \, m/s$. Since the ball is in free fall,its acceleration is equal to the acceleration due to gravity,$a = g = 10 \, m/s^{2}$ downwards.

$A$ car starts from rest and accelerates at $5 \, m/s^{2}$. At $t=4 \, s$,a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at $t=6 \, s$? (Take $g = 10 \, m/s^{2}$)

Similar Questions

List-$I$ describes four systems,each with two particles $A$ and $B$ in relative motion. List-$II$ gives possible magnitudes of their relative velocities (in $m s^{-1}$) at time $t = \frac{\pi}{3} s$. Which one of the following options is correct?

In a conical pendulum,the bob is rotated with different angular velocities and the tension in the string is calculated for different values of $\omega$. Which of the following is the correct graph between $T$ and $\omega$?

The second's hand of a watch has $6\, cm$ length. The speed of its tip and the magnitude of the difference in velocities of its tip at any two perpendicular positions will be respectively:

$A$ particle of mass $M$ is moving in a horizontal circle of radius $R$ with uniform speed $v$. When the particle moves from one point to a diametrically opposite point,its

$A$ particle is projected from the horizontal making an angle of $53^{\circ}$ with an initial velocity of $100\,m/s$. The time taken by the particle to make an angle of $45^{\circ}$ with the horizontal is $.........\,s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module