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(C) In a standard pack of $52$ cards,there are $4$ suits,each containing $13$ cards.The number of Diamond cards is $13$.The number of cards that are n

Vedclass · Accepted Answer

$\frac{3}{4}$

Vedclass · Answer

(C) In a standard pack of $52$ cards,there are $4$ suits,each containing $13$ cards.The number of Diamond cards is $13$.The number of cards that are not Diamonds is $52 - 13 = 39$.The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.$	ext{Probability (not a Diamond)} = \frac{	ext{Number of non-Diamond cards}}{	ext{Total number of cards}} = \frac{39}{52}$.Simplifying the fraction by dividing both numerator and denominator by $13$,we get $\frac{39 \div 13}{52 \div 13} = \frac{3}{4}$.

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability that the card drawn is not of Diamonds is ..............

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