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(B) The total number of outcomes when two dice are rolled is $6 	imes 6 = 36$.The prime numbers on a single die are $2, 3,$ and $5$.Let the event $E$

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$\frac{1}{4}$

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(B) The total number of outcomes when two dice are rolled is $6 	imes 6 = 36$.The prime numbers on a single die are $2, 3,$ and $5$.Let the event $E$ be that the numbers on both dice are prime. The favorable outcomes are:$(2, 2), (2, 3), (2, 5), (3, 2), (3, 3), (3, 5), (5, 2), (5, 3), (5, 5)$.The number of favorable outcomes is $m = 9$.The probability $P(E) = \frac{m}{n} = \frac{9}{36} = \frac{1}{4}$.

Two balanced dice are rolled simultaneously. Then,the probability that the numbers on both the dice are prime is ...........

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