A carriage driving in a fog passed a man who | vedclass

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(B) Let the speed of the carriage be $v 	ext{ km/h}$.Relative speed of the carriage with respect to the man is $(v - 3) 	ext{ km/h}$.In $4 	ext{ mi

Vedclass · Accepted Answer

$4\frac{1}{2}$

Vedclass · Answer

(B) Let the speed of the carriage be $v 	ext{ km/h}$.Relative speed of the carriage with respect to the man is $(v - 3) 	ext{ km/h}$.In $4 	ext{ minutes}$,the distance covered by the carriage relative to the man is $100 	ext{ m} = 0.1 	ext{ km}$.Time $t = 4 	ext{ minutes} = \frac{4}{60} 	ext{ hours} = \frac{1}{15} 	ext{ hours}$.Using the formula $	ext{Distance} = 	ext{Relative Speed} 	imes 	ext{Time}$:$0.1 = (v - 3) 	imes \frac{1}{15}$$v - 3 = 0.1 	imes 15 = 1.5$$v = 1.5 + 3 = 4.5 	ext{ km/h}$.Thus,the speed of the carriage is $4\frac{1}{2} 	ext{ km/h}$.

$A$ carriage driving in a fog passed a man who was walking at the rate of $3 \text{ km/h}$ in the same direction. He could see the carriage for $4 \text{ minutes}$ and it was visible to him up to a distance of $100 \text{ m}$. What was the speed of the carriage in $\text{km/h}$?

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